Windows 2003 Server 64bit Edition – LUN Alignment


Pre-requisites: Disk must be “Basic”.  Dynamic disks are not supported.

Configure Disk Alignment Value:

  1. Launch command window start -> run “cmd”
  2. type “diskpart”
  3. list disk
  4. select disk <disk number>
  5. list disk (confirm an * is next to the disk you selected)
  6. list partition (NO partitions should be visible. If partitions are listed then the disk may contain production data)
  7. create partition primary align=<alignment value ex: 32, 64, 128>
  8. assign letter=<free drive letter ex: G>
  9. list partition
  10. exit

Example configuration output:
C:\>diskpart
Microsoft DiskPart version 5.2.3790.3959
Copyright (C) 1999-2001 Microsoft Corporation.
On computer: Test1
DISKPART> list disk
Disk ###  Status      Size     Free     Dyn  Gpt
——–  ———-  ——-  ——-  —  —
Disk 5    Online        60 GB      0 B
DISKPART> select disk 5
Disk 5 is now the selected disk.
DISKPART> list partition
Partition ###  Type              Size     Offset
————-  —————-  ——-  ——-
Partition 1    Primary             60 GB   128 KB

Format Disk:

  1. Start -> run “diskmgmt.msc”
  2. Change the allocation size to match the segment size of the associated LUN.  A common segment size is 64KB
  3. Click Format
Advertisements

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s